What does the following fragment of C-program print?

char c[] = "GATE2011"; char *p =c; printf("%s", p + p[3] - p[1]) ;

(A) GATE2011
(B) E2011
(C) 2011
(D) 011

Answer: (C)
See comments for explanation.

char c[] = "GATE2011";  // p now has the base address string "GATE2011" char *p =c; // p[3] is 'E' and p[1] is 'A'.  // p[3] - p[1] = ASCII value of 'E' - ASCII value of 'A' = 4 // So the expression  p + p[3] - p[1] becomes p + 4 which is // base address of string "2011" printf("%s", p + p[3] - p[1]) ;