GATE EXAM PREPARATION IN "C" - Print “Even” or “Odd” without using conditional statement

Write a C/C++ program that accepts a number from the user and prints “Even” if the entered number is even and prints “Odd” if the number is odd. Your are not allowed to use any comparison (==, <, >..etc) or conditional (if, else, switch, ternary operator,..etc) statement.

Method 1
Below is a tricky code can be used to print “Even” or “Odd” accordingly.

#include<iostream> #include<conio.h>   using namespace std;   int main() {   char arr[2][5] = {"Even", "Odd"};   int no;   cout << "Enter a number: ";   cin >> no;   cout << arr[no%2];   getch();   return 0; }