char inchar = 'A';switch (inchar){case 'A' : printf ("choice A \n") ;case 'B' : printf ("choice B ") ;case 'C' :case 'D' :case 'E' :default: printf ("No Choice") ;} |
(A) No choice
(B) Choice A
(C) Choice A
Choice B No choice
(D) Program gives no output as it is erroneous
(B) Choice A
(C) Choice A
Choice B No choice
(D) Program gives no output as it is erroneous
Answer (C)
There is no break statement in case ‘A’. If a case is executed and it doesn’t contain break, then all the subsequent cases are executed until a break statement is found. That is why everything inside the switch is printed.
There is no break statement in case ‘A’. If a case is executed and it doesn’t contain break, then all the subsequent cases are executed until a break statement is found. That is why everything inside the switch is printed.
No comments:
Post a Comment