GATE EXAM PREPARATION IN "C" - How to print % using printf()?

Here is the standard prototype of printf function in C.

          int printf(const char *format, ...);

The format string is composed of zero or more directives: ordinary characters (not %), which are copied unchanged to the output stream; and conversion specifications, each of argument (and it is an error if insufficiently many arguments are given).

The character % is followed by one of the following characters.

The flag character
The field width
The precision
The length modifier
The conversion specifier:

A `%' is written. No argument is converted. The complete conversion specification is`%%'.

So we can print “%” using “%%”

/* Program to print %*/ #include<stdio.h> /* Program to print %*/ int main() {    printf("%%");    getchar();    return 0; }

We can also print “%” using below.

printf("%c", '%'); printf("%s", "%");