The value of j at the end of the execution of the following C program.
int incr (int i){ static int count = 0; count = count + i; return (count);}main (){ int i,j; for (i = 0; i <=4; i++) j = incr(i);}
(a) 10
(b) 4
(c) 6 (d) 7
Answer (a)
Explanation: count is static variable in incr(). Statement static int count = 0 will assign count to 0 only in first call. Other calls to this function will take the old values of count. Count will become 0 after the call incr(0) Count will become 1 after the call incr(1) Count will become 3 after the call incr(2) Count will become 6 after the call incr(3) Count will become 10 after the call incr(4) |
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